A radiation detector which is located 6.29 meters from a radiation source indicates a radiation intensity of 311 mCi (millicuries). What would the radiation intensity be if the detector was 30.6 meters from the source?What would the radiation intensity be if the detector was 30.6 meters from the source?
The detected radiation is inversely proportional to the square of the distance from the source to the detector. Hence the answer is:
(311 mCi)*(6.29/30.6)^2 = 13.1 mCi
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