What is the highest state the electron can be promoted to by this radiation?

If a H atom in its ground state is illuminated with electromagnetic radiation of wavelength 97.44nm, what is the highest state the electron can be promoted to by this radiation?What is the highest state the electron can be promoted to by this radiation?
Your photon has an energy of:



E = hv = hc/l (where v is frequency, l is wavelength, h is Plank's constant and c is speed of light)



This gives E (photon) = 12.72eV



The energy at each level is found as:



E = hcR (Z^2)/(n^2) (where Z is the charge, R is the Rydberg constant and n is the energy level (actually it is the principal quantum number))



But since hcR = -13.6eV (and Z = 1 for the H atom), this is just: E = -13.6eV/(n^2)



This leads to the energy relation to move from one state to another as:



Es = E(final) - E(initial) = -13.6eV/(n-final^2) - (-)13.6eV/(n-initial^2)



This is applied to your case so that we can use the total energy available (supplied by photon) to find the E(final) as such:



12.72eV = -13.6eV/(n^2) + 13.6eV (n=1 for ground state)



or: n^2 = 15.49 -%26gt; n = 3.94



So, the electron could get to the third level with the excess energy going towards change in momentum. Now, energy takes all kinds of forms thermal, mechanical, etc., and so the electron might actually make it to the fourth on a good day or it might be stuck on the second on a bad. It gets complicated. What you should consider is what would happen if a photon had 13.6eV energy. By putting this in the equation above you will have a divide by zero situation which has a solution of infinity. In other words, the electron would be freed and the atom would be ionized (on a good day). Hope this helped you understand.

catalytic converter

planet hollywood